What are the numbers divisible by 1009?
1009, 2018, 3027, 4036, 5045, 6054, 7063, 8072, 9081, 10090, 11099, 12108, 13117, 14126, 15135, 16144, 17153, 18162, 19171, 20180, 21189, 22198, 23207, 24216, 25225, 26234, 27243, 28252, 29261, 30270, 31279, 32288, 33297, 34306, 35315, 36324, 37333, 38342, 39351, 40360, 41369, 42378, 43387, 44396, 45405, 46414, 47423, 48432, 49441, 50450, 51459, 52468, 53477, 54486, 55495, 56504, 57513, 58522, 59531, 60540, 61549, 62558, 63567, 64576, 65585, 66594, 67603, 68612, 69621, 70630, 71639, 72648, 73657, 74666, 75675, 76684, 77693, 78702, 79711, 80720, 81729, 82738, 83747, 84756, 85765, 86774, 87783, 88792, 89801, 90810, 91819, 92828, 93837, 94846, 95855, 96864, 97873, 98882, 99891
- There is a total of 99 numbers (up to 100000) that are divisible by 1009.
- The sum of these numbers is 4994550.
- The arithmetic mean of these numbers is 50450.
How to find the numbers divisible by 1009?
Finding all the numbers that can be divided by 1009 is essentially the same as searching for the multiples of 1009: if a number N is a multiple of 1009, then 1009 is a divisor of N.
Indeed, if we assume that N is a multiple of 1009, this means there exists an integer k such that:
Conversely, the result of N divided by 1009 is this same integer k (without any remainder):
From this we can see that, theoretically, there's an infinite quantity of multiples of 1009 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).
However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1009 less than 100000):
- 1 × 1009 = 1009
- 2 × 1009 = 2018
- 3 × 1009 = 3027
- ...
- 98 × 1009 = 98882
- 99 × 1009 = 99891