What are the numbers divisible by 1012?

1012, 2024, 3036, 4048, 5060, 6072, 7084, 8096, 9108, 10120, 11132, 12144, 13156, 14168, 15180, 16192, 17204, 18216, 19228, 20240, 21252, 22264, 23276, 24288, 25300, 26312, 27324, 28336, 29348, 30360, 31372, 32384, 33396, 34408, 35420, 36432, 37444, 38456, 39468, 40480, 41492, 42504, 43516, 44528, 45540, 46552, 47564, 48576, 49588, 50600, 51612, 52624, 53636, 54648, 55660, 56672, 57684, 58696, 59708, 60720, 61732, 62744, 63756, 64768, 65780, 66792, 67804, 68816, 69828, 70840, 71852, 72864, 73876, 74888, 75900, 76912, 77924, 78936, 79948, 80960, 81972, 82984, 83996, 85008, 86020, 87032, 88044, 89056, 90068, 91080, 92092, 93104, 94116, 95128, 96140, 97152, 98164, 99176

There is a total of 98 numbers (up to 100000) that are divisible by 1012.
The sum of these numbers is 4909212.
The arithmetic mean of these numbers is 50094.

How to find the numbers divisible by 1012?

Finding all the numbers that can be divided by 1012 is essentially the same as searching for the multiples of 1012: if a number N is a multiple of 1012, then 1012 is a divisor of N.

Indeed, if we assume that N is a multiple of 1012, this means there exists an integer k such that:

$k \times 1012 = N$

Conversely, the result of N divided by 1012 is this same integer k (without any remainder):

$k = \frac{N}{1012}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1012 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1012 less than 100000):

1 × 1012 = 1012
2 × 1012 = 2024
3 × 1012 = 3036
...
97 × 1012 = 98164
98 × 1012 = 99176