What are the numbers divisible by 1018?

1018, 2036, 3054, 4072, 5090, 6108, 7126, 8144, 9162, 10180, 11198, 12216, 13234, 14252, 15270, 16288, 17306, 18324, 19342, 20360, 21378, 22396, 23414, 24432, 25450, 26468, 27486, 28504, 29522, 30540, 31558, 32576, 33594, 34612, 35630, 36648, 37666, 38684, 39702, 40720, 41738, 42756, 43774, 44792, 45810, 46828, 47846, 48864, 49882, 50900, 51918, 52936, 53954, 54972, 55990, 57008, 58026, 59044, 60062, 61080, 62098, 63116, 64134, 65152, 66170, 67188, 68206, 69224, 70242, 71260, 72278, 73296, 74314, 75332, 76350, 77368, 78386, 79404, 80422, 81440, 82458, 83476, 84494, 85512, 86530, 87548, 88566, 89584, 90602, 91620, 92638, 93656, 94674, 95692, 96710, 97728, 98746, 99764

There is a total of 98 numbers (up to 100000) that are divisible by 1018.
The sum of these numbers is 4938318.
The arithmetic mean of these numbers is 50391.

How to find the numbers divisible by 1018?

Finding all the numbers that can be divided by 1018 is essentially the same as searching for the multiples of 1018: if a number N is a multiple of 1018, then 1018 is a divisor of N.

Indeed, if we assume that N is a multiple of 1018, this means there exists an integer k such that:

$k \times 1018 = N$

Conversely, the result of N divided by 1018 is this same integer k (without any remainder):

$k = \frac{N}{1018}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1018 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1018 less than 100000):

1 × 1018 = 1018
2 × 1018 = 2036
3 × 1018 = 3054
...
97 × 1018 = 98746
98 × 1018 = 99764