What are the numbers divisible by 1021?

1021, 2042, 3063, 4084, 5105, 6126, 7147, 8168, 9189, 10210, 11231, 12252, 13273, 14294, 15315, 16336, 17357, 18378, 19399, 20420, 21441, 22462, 23483, 24504, 25525, 26546, 27567, 28588, 29609, 30630, 31651, 32672, 33693, 34714, 35735, 36756, 37777, 38798, 39819, 40840, 41861, 42882, 43903, 44924, 45945, 46966, 47987, 49008, 50029, 51050, 52071, 53092, 54113, 55134, 56155, 57176, 58197, 59218, 60239, 61260, 62281, 63302, 64323, 65344, 66365, 67386, 68407, 69428, 70449, 71470, 72491, 73512, 74533, 75554, 76575, 77596, 78617, 79638, 80659, 81680, 82701, 83722, 84743, 85764, 86785, 87806, 88827, 89848, 90869, 91890, 92911, 93932, 94953, 95974, 96995, 98016, 99037

There is a total of 97 numbers (up to 100000) that are divisible by 1021.
The sum of these numbers is 4852813.
The arithmetic mean of these numbers is 50029.

How to find the numbers divisible by 1021?

Finding all the numbers that can be divided by 1021 is essentially the same as searching for the multiples of 1021: if a number N is a multiple of 1021, then 1021 is a divisor of N.

Indeed, if we assume that N is a multiple of 1021, this means there exists an integer k such that:

$k \times 1021 = N$

Conversely, the result of N divided by 1021 is this same integer k (without any remainder):

$k = \frac{N}{1021}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1021 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1021 less than 100000):

1 × 1021 = 1021
2 × 1021 = 2042
3 × 1021 = 3063
...
96 × 1021 = 98016
97 × 1021 = 99037