What are the numbers divisible by 1028?

1028, 2056, 3084, 4112, 5140, 6168, 7196, 8224, 9252, 10280, 11308, 12336, 13364, 14392, 15420, 16448, 17476, 18504, 19532, 20560, 21588, 22616, 23644, 24672, 25700, 26728, 27756, 28784, 29812, 30840, 31868, 32896, 33924, 34952, 35980, 37008, 38036, 39064, 40092, 41120, 42148, 43176, 44204, 45232, 46260, 47288, 48316, 49344, 50372, 51400, 52428, 53456, 54484, 55512, 56540, 57568, 58596, 59624, 60652, 61680, 62708, 63736, 64764, 65792, 66820, 67848, 68876, 69904, 70932, 71960, 72988, 74016, 75044, 76072, 77100, 78128, 79156, 80184, 81212, 82240, 83268, 84296, 85324, 86352, 87380, 88408, 89436, 90464, 91492, 92520, 93548, 94576, 95604, 96632, 97660, 98688, 99716

There is a total of 97 numbers (up to 100000) that are divisible by 1028.
The sum of these numbers is 4886084.
The arithmetic mean of these numbers is 50372.

How to find the numbers divisible by 1028?

Finding all the numbers that can be divided by 1028 is essentially the same as searching for the multiples of 1028: if a number N is a multiple of 1028, then 1028 is a divisor of N.

Indeed, if we assume that N is a multiple of 1028, this means there exists an integer k such that:

$k \times 1028 = N$

Conversely, the result of N divided by 1028 is this same integer k (without any remainder):

$k = \frac{N}{1028}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1028 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1028 less than 100000):

1 × 1028 = 1028
2 × 1028 = 2056
3 × 1028 = 3084
...
96 × 1028 = 98688
97 × 1028 = 99716