What are the numbers divisible by 1042?

1042, 2084, 3126, 4168, 5210, 6252, 7294, 8336, 9378, 10420, 11462, 12504, 13546, 14588, 15630, 16672, 17714, 18756, 19798, 20840, 21882, 22924, 23966, 25008, 26050, 27092, 28134, 29176, 30218, 31260, 32302, 33344, 34386, 35428, 36470, 37512, 38554, 39596, 40638, 41680, 42722, 43764, 44806, 45848, 46890, 47932, 48974, 50016, 51058, 52100, 53142, 54184, 55226, 56268, 57310, 58352, 59394, 60436, 61478, 62520, 63562, 64604, 65646, 66688, 67730, 68772, 69814, 70856, 71898, 72940, 73982, 75024, 76066, 77108, 78150, 79192, 80234, 81276, 82318, 83360, 84402, 85444, 86486, 87528, 88570, 89612, 90654, 91696, 92738, 93780, 94822, 95864, 96906, 97948, 98990

There is a total of 95 numbers (up to 100000) that are divisible by 1042.
The sum of these numbers is 4751520.
The arithmetic mean of these numbers is 50016.

How to find the numbers divisible by 1042?

Finding all the numbers that can be divided by 1042 is essentially the same as searching for the multiples of 1042: if a number N is a multiple of 1042, then 1042 is a divisor of N.

Indeed, if we assume that N is a multiple of 1042, this means there exists an integer k such that:

$k \times 1042 = N$

Conversely, the result of N divided by 1042 is this same integer k (without any remainder):

$k = \frac{N}{1042}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1042 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1042 less than 100000):

1 × 1042 = 1042
2 × 1042 = 2084
3 × 1042 = 3126
...
94 × 1042 = 97948
95 × 1042 = 98990