What are the numbers divisible by 1045?

1045, 2090, 3135, 4180, 5225, 6270, 7315, 8360, 9405, 10450, 11495, 12540, 13585, 14630, 15675, 16720, 17765, 18810, 19855, 20900, 21945, 22990, 24035, 25080, 26125, 27170, 28215, 29260, 30305, 31350, 32395, 33440, 34485, 35530, 36575, 37620, 38665, 39710, 40755, 41800, 42845, 43890, 44935, 45980, 47025, 48070, 49115, 50160, 51205, 52250, 53295, 54340, 55385, 56430, 57475, 58520, 59565, 60610, 61655, 62700, 63745, 64790, 65835, 66880, 67925, 68970, 70015, 71060, 72105, 73150, 74195, 75240, 76285, 77330, 78375, 79420, 80465, 81510, 82555, 83600, 84645, 85690, 86735, 87780, 88825, 89870, 90915, 91960, 93005, 94050, 95095, 96140, 97185, 98230, 99275

There is a total of 95 numbers (up to 100000) that are divisible by 1045.
The sum of these numbers is 4765200.
The arithmetic mean of these numbers is 50160.

How to find the numbers divisible by 1045?

Finding all the numbers that can be divided by 1045 is essentially the same as searching for the multiples of 1045: if a number N is a multiple of 1045, then 1045 is a divisor of N.

Indeed, if we assume that N is a multiple of 1045, this means there exists an integer k such that:

$k \times 1045 = N$

Conversely, the result of N divided by 1045 is this same integer k (without any remainder):

$k = \frac{N}{1045}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1045 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1045 less than 100000):

1 × 1045 = 1045
2 × 1045 = 2090
3 × 1045 = 3135
...
94 × 1045 = 98230
95 × 1045 = 99275