What are the numbers divisible by 1047?

1047, 2094, 3141, 4188, 5235, 6282, 7329, 8376, 9423, 10470, 11517, 12564, 13611, 14658, 15705, 16752, 17799, 18846, 19893, 20940, 21987, 23034, 24081, 25128, 26175, 27222, 28269, 29316, 30363, 31410, 32457, 33504, 34551, 35598, 36645, 37692, 38739, 39786, 40833, 41880, 42927, 43974, 45021, 46068, 47115, 48162, 49209, 50256, 51303, 52350, 53397, 54444, 55491, 56538, 57585, 58632, 59679, 60726, 61773, 62820, 63867, 64914, 65961, 67008, 68055, 69102, 70149, 71196, 72243, 73290, 74337, 75384, 76431, 77478, 78525, 79572, 80619, 81666, 82713, 83760, 84807, 85854, 86901, 87948, 88995, 90042, 91089, 92136, 93183, 94230, 95277, 96324, 97371, 98418, 99465

There is a total of 95 numbers (up to 100000) that are divisible by 1047.
The sum of these numbers is 4774320.
The arithmetic mean of these numbers is 50256.

How to find the numbers divisible by 1047?

Finding all the numbers that can be divided by 1047 is essentially the same as searching for the multiples of 1047: if a number N is a multiple of 1047, then 1047 is a divisor of N.

Indeed, if we assume that N is a multiple of 1047, this means there exists an integer k such that:

$k \times 1047 = N$

Conversely, the result of N divided by 1047 is this same integer k (without any remainder):

$k = \frac{N}{1047}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1047 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1047 less than 100000):

1 × 1047 = 1047
2 × 1047 = 2094
3 × 1047 = 3141
...
94 × 1047 = 98418
95 × 1047 = 99465