What are the numbers divisible by 1049?

1049, 2098, 3147, 4196, 5245, 6294, 7343, 8392, 9441, 10490, 11539, 12588, 13637, 14686, 15735, 16784, 17833, 18882, 19931, 20980, 22029, 23078, 24127, 25176, 26225, 27274, 28323, 29372, 30421, 31470, 32519, 33568, 34617, 35666, 36715, 37764, 38813, 39862, 40911, 41960, 43009, 44058, 45107, 46156, 47205, 48254, 49303, 50352, 51401, 52450, 53499, 54548, 55597, 56646, 57695, 58744, 59793, 60842, 61891, 62940, 63989, 65038, 66087, 67136, 68185, 69234, 70283, 71332, 72381, 73430, 74479, 75528, 76577, 77626, 78675, 79724, 80773, 81822, 82871, 83920, 84969, 86018, 87067, 88116, 89165, 90214, 91263, 92312, 93361, 94410, 95459, 96508, 97557, 98606, 99655

There is a total of 95 numbers (up to 100000) that are divisible by 1049.
The sum of these numbers is 4783440.
The arithmetic mean of these numbers is 50352.

How to find the numbers divisible by 1049?

Finding all the numbers that can be divided by 1049 is essentially the same as searching for the multiples of 1049: if a number N is a multiple of 1049, then 1049 is a divisor of N.

Indeed, if we assume that N is a multiple of 1049, this means there exists an integer k such that:

$k \times 1049 = N$

Conversely, the result of N divided by 1049 is this same integer k (without any remainder):

$k = \frac{N}{1049}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1049 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1049 less than 100000):

1 × 1049 = 1049
2 × 1049 = 2098
3 × 1049 = 3147
...
94 × 1049 = 98606
95 × 1049 = 99655