What are the numbers divisible by 1051?

1051, 2102, 3153, 4204, 5255, 6306, 7357, 8408, 9459, 10510, 11561, 12612, 13663, 14714, 15765, 16816, 17867, 18918, 19969, 21020, 22071, 23122, 24173, 25224, 26275, 27326, 28377, 29428, 30479, 31530, 32581, 33632, 34683, 35734, 36785, 37836, 38887, 39938, 40989, 42040, 43091, 44142, 45193, 46244, 47295, 48346, 49397, 50448, 51499, 52550, 53601, 54652, 55703, 56754, 57805, 58856, 59907, 60958, 62009, 63060, 64111, 65162, 66213, 67264, 68315, 69366, 70417, 71468, 72519, 73570, 74621, 75672, 76723, 77774, 78825, 79876, 80927, 81978, 83029, 84080, 85131, 86182, 87233, 88284, 89335, 90386, 91437, 92488, 93539, 94590, 95641, 96692, 97743, 98794, 99845

There is a total of 95 numbers (up to 100000) that are divisible by 1051.
The sum of these numbers is 4792560.
The arithmetic mean of these numbers is 50448.

How to find the numbers divisible by 1051?

Finding all the numbers that can be divided by 1051 is essentially the same as searching for the multiples of 1051: if a number N is a multiple of 1051, then 1051 is a divisor of N.

Indeed, if we assume that N is a multiple of 1051, this means there exists an integer k such that:

$k \times 1051 = N$

Conversely, the result of N divided by 1051 is this same integer k (without any remainder):

$k = \frac{N}{1051}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1051 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1051 less than 100000):

1 × 1051 = 1051
2 × 1051 = 2102
3 × 1051 = 3153
...
94 × 1051 = 98794
95 × 1051 = 99845