What are the numbers divisible by 1053?

1053, 2106, 3159, 4212, 5265, 6318, 7371, 8424, 9477, 10530, 11583, 12636, 13689, 14742, 15795, 16848, 17901, 18954, 20007, 21060, 22113, 23166, 24219, 25272, 26325, 27378, 28431, 29484, 30537, 31590, 32643, 33696, 34749, 35802, 36855, 37908, 38961, 40014, 41067, 42120, 43173, 44226, 45279, 46332, 47385, 48438, 49491, 50544, 51597, 52650, 53703, 54756, 55809, 56862, 57915, 58968, 60021, 61074, 62127, 63180, 64233, 65286, 66339, 67392, 68445, 69498, 70551, 71604, 72657, 73710, 74763, 75816, 76869, 77922, 78975, 80028, 81081, 82134, 83187, 84240, 85293, 86346, 87399, 88452, 89505, 90558, 91611, 92664, 93717, 94770, 95823, 96876, 97929, 98982

There is a total of 94 numbers (up to 100000) that are divisible by 1053.
The sum of these numbers is 4701645.
The arithmetic mean of these numbers is 50017.5.

How to find the numbers divisible by 1053?

Finding all the numbers that can be divided by 1053 is essentially the same as searching for the multiples of 1053: if a number N is a multiple of 1053, then 1053 is a divisor of N.

Indeed, if we assume that N is a multiple of 1053, this means there exists an integer k such that:

$k \times 1053 = N$

Conversely, the result of N divided by 1053 is this same integer k (without any remainder):

$k = \frac{N}{1053}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1053 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1053 less than 100000):

1 × 1053 = 1053
2 × 1053 = 2106
3 × 1053 = 3159
...
93 × 1053 = 97929
94 × 1053 = 98982