What are the numbers divisible by 1057?

1057, 2114, 3171, 4228, 5285, 6342, 7399, 8456, 9513, 10570, 11627, 12684, 13741, 14798, 15855, 16912, 17969, 19026, 20083, 21140, 22197, 23254, 24311, 25368, 26425, 27482, 28539, 29596, 30653, 31710, 32767, 33824, 34881, 35938, 36995, 38052, 39109, 40166, 41223, 42280, 43337, 44394, 45451, 46508, 47565, 48622, 49679, 50736, 51793, 52850, 53907, 54964, 56021, 57078, 58135, 59192, 60249, 61306, 62363, 63420, 64477, 65534, 66591, 67648, 68705, 69762, 70819, 71876, 72933, 73990, 75047, 76104, 77161, 78218, 79275, 80332, 81389, 82446, 83503, 84560, 85617, 86674, 87731, 88788, 89845, 90902, 91959, 93016, 94073, 95130, 96187, 97244, 98301, 99358

There is a total of 94 numbers (up to 100000) that are divisible by 1057.
The sum of these numbers is 4719505.
The arithmetic mean of these numbers is 50207.5.

How to find the numbers divisible by 1057?

Finding all the numbers that can be divided by 1057 is essentially the same as searching for the multiples of 1057: if a number N is a multiple of 1057, then 1057 is a divisor of N.

Indeed, if we assume that N is a multiple of 1057, this means there exists an integer k such that:

$k \times 1057 = N$

Conversely, the result of N divided by 1057 is this same integer k (without any remainder):

$k = \frac{N}{1057}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1057 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1057 less than 100000):

1 × 1057 = 1057
2 × 1057 = 2114
3 × 1057 = 3171
...
93 × 1057 = 98301
94 × 1057 = 99358