What are the numbers divisible by 1060?

1060, 2120, 3180, 4240, 5300, 6360, 7420, 8480, 9540, 10600, 11660, 12720, 13780, 14840, 15900, 16960, 18020, 19080, 20140, 21200, 22260, 23320, 24380, 25440, 26500, 27560, 28620, 29680, 30740, 31800, 32860, 33920, 34980, 36040, 37100, 38160, 39220, 40280, 41340, 42400, 43460, 44520, 45580, 46640, 47700, 48760, 49820, 50880, 51940, 53000, 54060, 55120, 56180, 57240, 58300, 59360, 60420, 61480, 62540, 63600, 64660, 65720, 66780, 67840, 68900, 69960, 71020, 72080, 73140, 74200, 75260, 76320, 77380, 78440, 79500, 80560, 81620, 82680, 83740, 84800, 85860, 86920, 87980, 89040, 90100, 91160, 92220, 93280, 94340, 95400, 96460, 97520, 98580, 99640

There is a total of 94 numbers (up to 100000) that are divisible by 1060.
The sum of these numbers is 4732900.
The arithmetic mean of these numbers is 50350.

How to find the numbers divisible by 1060?

Finding all the numbers that can be divided by 1060 is essentially the same as searching for the multiples of 1060: if a number N is a multiple of 1060, then 1060 is a divisor of N.

Indeed, if we assume that N is a multiple of 1060, this means there exists an integer k such that:

$k \times 1060 = N$

Conversely, the result of N divided by 1060 is this same integer k (without any remainder):

$k = \frac{N}{1060}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1060 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1060 less than 100000):

1 × 1060 = 1060
2 × 1060 = 2120
3 × 1060 = 3180
...
93 × 1060 = 98580
94 × 1060 = 99640