What are the numbers divisible by 1065?

1065, 2130, 3195, 4260, 5325, 6390, 7455, 8520, 9585, 10650, 11715, 12780, 13845, 14910, 15975, 17040, 18105, 19170, 20235, 21300, 22365, 23430, 24495, 25560, 26625, 27690, 28755, 29820, 30885, 31950, 33015, 34080, 35145, 36210, 37275, 38340, 39405, 40470, 41535, 42600, 43665, 44730, 45795, 46860, 47925, 48990, 50055, 51120, 52185, 53250, 54315, 55380, 56445, 57510, 58575, 59640, 60705, 61770, 62835, 63900, 64965, 66030, 67095, 68160, 69225, 70290, 71355, 72420, 73485, 74550, 75615, 76680, 77745, 78810, 79875, 80940, 82005, 83070, 84135, 85200, 86265, 87330, 88395, 89460, 90525, 91590, 92655, 93720, 94785, 95850, 96915, 97980, 99045

There is a total of 93 numbers (up to 100000) that are divisible by 1065.
The sum of these numbers is 4655115.
The arithmetic mean of these numbers is 50055.

How to find the numbers divisible by 1065?

Finding all the numbers that can be divided by 1065 is essentially the same as searching for the multiples of 1065: if a number N is a multiple of 1065, then 1065 is a divisor of N.

Indeed, if we assume that N is a multiple of 1065, this means there exists an integer k such that:

$k \times 1065 = N$

Conversely, the result of N divided by 1065 is this same integer k (without any remainder):

$k = \frac{N}{1065}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1065 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1065 less than 100000):

1 × 1065 = 1065
2 × 1065 = 2130
3 × 1065 = 3195
...
92 × 1065 = 97980
93 × 1065 = 99045