What are the numbers divisible by 1071?

1071, 2142, 3213, 4284, 5355, 6426, 7497, 8568, 9639, 10710, 11781, 12852, 13923, 14994, 16065, 17136, 18207, 19278, 20349, 21420, 22491, 23562, 24633, 25704, 26775, 27846, 28917, 29988, 31059, 32130, 33201, 34272, 35343, 36414, 37485, 38556, 39627, 40698, 41769, 42840, 43911, 44982, 46053, 47124, 48195, 49266, 50337, 51408, 52479, 53550, 54621, 55692, 56763, 57834, 58905, 59976, 61047, 62118, 63189, 64260, 65331, 66402, 67473, 68544, 69615, 70686, 71757, 72828, 73899, 74970, 76041, 77112, 78183, 79254, 80325, 81396, 82467, 83538, 84609, 85680, 86751, 87822, 88893, 89964, 91035, 92106, 93177, 94248, 95319, 96390, 97461, 98532, 99603

There is a total of 93 numbers (up to 100000) that are divisible by 1071.
The sum of these numbers is 4681341.
The arithmetic mean of these numbers is 50337.

How to find the numbers divisible by 1071?

Finding all the numbers that can be divided by 1071 is essentially the same as searching for the multiples of 1071: if a number N is a multiple of 1071, then 1071 is a divisor of N.

Indeed, if we assume that N is a multiple of 1071, this means there exists an integer k such that:

$k \times 1071 = N$

Conversely, the result of N divided by 1071 is this same integer k (without any remainder):

$k = \frac{N}{1071}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1071 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1071 less than 100000):

1 × 1071 = 1071
2 × 1071 = 2142
3 × 1071 = 3213
...
92 × 1071 = 98532
93 × 1071 = 99603