What are the numbers divisible by 1075?

1075, 2150, 3225, 4300, 5375, 6450, 7525, 8600, 9675, 10750, 11825, 12900, 13975, 15050, 16125, 17200, 18275, 19350, 20425, 21500, 22575, 23650, 24725, 25800, 26875, 27950, 29025, 30100, 31175, 32250, 33325, 34400, 35475, 36550, 37625, 38700, 39775, 40850, 41925, 43000, 44075, 45150, 46225, 47300, 48375, 49450, 50525, 51600, 52675, 53750, 54825, 55900, 56975, 58050, 59125, 60200, 61275, 62350, 63425, 64500, 65575, 66650, 67725, 68800, 69875, 70950, 72025, 73100, 74175, 75250, 76325, 77400, 78475, 79550, 80625, 81700, 82775, 83850, 84925, 86000, 87075, 88150, 89225, 90300, 91375, 92450, 93525, 94600, 95675, 96750, 97825, 98900, 99975

There is a total of 93 numbers (up to 100000) that are divisible by 1075.
The sum of these numbers is 4698825.
The arithmetic mean of these numbers is 50525.

How to find the numbers divisible by 1075?

Finding all the numbers that can be divided by 1075 is essentially the same as searching for the multiples of 1075: if a number N is a multiple of 1075, then 1075 is a divisor of N.

Indeed, if we assume that N is a multiple of 1075, this means there exists an integer k such that:

$k \times 1075 = N$

Conversely, the result of N divided by 1075 is this same integer k (without any remainder):

$k = \frac{N}{1075}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 1075 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 1075 less than 100000):

1 × 1075 = 1075
2 × 1075 = 2150
3 × 1075 = 3225
...
92 × 1075 = 98900
93 × 1075 = 99975