What are the numbers divisible by 2002?

2002, 4004, 6006, 8008, 10010, 12012, 14014, 16016, 18018, 20020, 22022, 24024, 26026, 28028, 30030, 32032, 34034, 36036, 38038, 40040, 42042, 44044, 46046, 48048, 50050, 52052, 54054, 56056, 58058, 60060, 62062, 64064, 66066, 68068, 70070, 72072, 74074, 76076, 78078, 80080, 82082, 84084, 86086, 88088, 90090, 92092, 94094, 96096, 98098

There is a total of 49 numbers (up to 100000) that are divisible by 2002.
The sum of these numbers is 2452450.
The arithmetic mean of these numbers is 50050.

How to find the numbers divisible by 2002?

Finding all the numbers that can be divided by 2002 is essentially the same as searching for the multiples of 2002: if a number N is a multiple of 2002, then 2002 is a divisor of N.

Indeed, if we assume that N is a multiple of 2002, this means there exists an integer k such that:

$k \times 2002 = N$

Conversely, the result of N divided by 2002 is this same integer k (without any remainder):

$k = \frac{N}{2002}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 2002 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 2002 less than 100000):

1 × 2002 = 2002
2 × 2002 = 4004
3 × 2002 = 6006
...
48 × 2002 = 96096
49 × 2002 = 98098