What are the numbers divisible by 2015?

2015, 4030, 6045, 8060, 10075, 12090, 14105, 16120, 18135, 20150, 22165, 24180, 26195, 28210, 30225, 32240, 34255, 36270, 38285, 40300, 42315, 44330, 46345, 48360, 50375, 52390, 54405, 56420, 58435, 60450, 62465, 64480, 66495, 68510, 70525, 72540, 74555, 76570, 78585, 80600, 82615, 84630, 86645, 88660, 90675, 92690, 94705, 96720, 98735

There is a total of 49 numbers (up to 100000) that are divisible by 2015.
The sum of these numbers is 2468375.
The arithmetic mean of these numbers is 50375.

How to find the numbers divisible by 2015?

Finding all the numbers that can be divided by 2015 is essentially the same as searching for the multiples of 2015: if a number N is a multiple of 2015, then 2015 is a divisor of N.

Indeed, if we assume that N is a multiple of 2015, this means there exists an integer k such that:

$k \times 2015 = N$

Conversely, the result of N divided by 2015 is this same integer k (without any remainder):

$k = \frac{N}{2015}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 2015 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 2015 less than 100000):

1 × 2015 = 2015
2 × 2015 = 4030
3 × 2015 = 6045
...
48 × 2015 = 96720
49 × 2015 = 98735