What are the numbers divisible by 2018?

2018, 4036, 6054, 8072, 10090, 12108, 14126, 16144, 18162, 20180, 22198, 24216, 26234, 28252, 30270, 32288, 34306, 36324, 38342, 40360, 42378, 44396, 46414, 48432, 50450, 52468, 54486, 56504, 58522, 60540, 62558, 64576, 66594, 68612, 70630, 72648, 74666, 76684, 78702, 80720, 82738, 84756, 86774, 88792, 90810, 92828, 94846, 96864, 98882

There is a total of 49 numbers (up to 100000) that are divisible by 2018.
The sum of these numbers is 2472050.
The arithmetic mean of these numbers is 50450.

How to find the numbers divisible by 2018?

Finding all the numbers that can be divided by 2018 is essentially the same as searching for the multiples of 2018: if a number N is a multiple of 2018, then 2018 is a divisor of N.

Indeed, if we assume that N is a multiple of 2018, this means there exists an integer k such that:

$k \times 2018 = N$

Conversely, the result of N divided by 2018 is this same integer k (without any remainder):

$k = \frac{N}{2018}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 2018 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 2018 less than 100000):

1 × 2018 = 2018
2 × 2018 = 4036
3 × 2018 = 6054
...
48 × 2018 = 96864
49 × 2018 = 98882