What are the numbers divisible by 2075?

2075, 4150, 6225, 8300, 10375, 12450, 14525, 16600, 18675, 20750, 22825, 24900, 26975, 29050, 31125, 33200, 35275, 37350, 39425, 41500, 43575, 45650, 47725, 49800, 51875, 53950, 56025, 58100, 60175, 62250, 64325, 66400, 68475, 70550, 72625, 74700, 76775, 78850, 80925, 83000, 85075, 87150, 89225, 91300, 93375, 95450, 97525, 99600

There is a total of 48 numbers (up to 100000) that are divisible by 2075.
The sum of these numbers is 2440200.
The arithmetic mean of these numbers is 50837.5.

How to find the numbers divisible by 2075?

Finding all the numbers that can be divided by 2075 is essentially the same as searching for the multiples of 2075: if a number N is a multiple of 2075, then 2075 is a divisor of N.

Indeed, if we assume that N is a multiple of 2075, this means there exists an integer k such that:

$k \times 2075 = N$

Conversely, the result of N divided by 2075 is this same integer k (without any remainder):

$k = \frac{N}{2075}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 2075 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 2075 less than 100000):

1 × 2075 = 2075
2 × 2075 = 4150
3 × 2075 = 6225
...
47 × 2075 = 97525
48 × 2075 = 99600