What are the numbers divisible by 2112?

2112, 4224, 6336, 8448, 10560, 12672, 14784, 16896, 19008, 21120, 23232, 25344, 27456, 29568, 31680, 33792, 35904, 38016, 40128, 42240, 44352, 46464, 48576, 50688, 52800, 54912, 57024, 59136, 61248, 63360, 65472, 67584, 69696, 71808, 73920, 76032, 78144, 80256, 82368, 84480, 86592, 88704, 90816, 92928, 95040, 97152, 99264

There is a total of 47 numbers (up to 100000) that are divisible by 2112.
The sum of these numbers is 2382336.
The arithmetic mean of these numbers is 50688.

How to find the numbers divisible by 2112?

Finding all the numbers that can be divided by 2112 is essentially the same as searching for the multiples of 2112: if a number N is a multiple of 2112, then 2112 is a divisor of N.

Indeed, if we assume that N is a multiple of 2112, this means there exists an integer k such that:

$k \times 2112 = N$

Conversely, the result of N divided by 2112 is this same integer k (without any remainder):

$k = \frac{N}{2112}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 2112 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 2112 less than 100000):

1 × 2112 = 2112
2 × 2112 = 4224
3 × 2112 = 6336
...
46 × 2112 = 97152
47 × 2112 = 99264