What are the numbers divisible by 4008?

4008, 8016, 12024, 16032, 20040, 24048, 28056, 32064, 36072, 40080, 44088, 48096, 52104, 56112, 60120, 64128, 68136, 72144, 76152, 80160, 84168, 88176, 92184, 96192

There is a total of 24 numbers (up to 100000) that are divisible by 4008.
The sum of these numbers is 1202400.
The arithmetic mean of these numbers is 50100.

How to find the numbers divisible by 4008?

Finding all the numbers that can be divided by 4008 is essentially the same as searching for the multiples of 4008: if a number N is a multiple of 4008, then 4008 is a divisor of N.

Indeed, if we assume that N is a multiple of 4008, this means there exists an integer k such that:

$k \times 4008 = N$

Conversely, the result of N divided by 4008 is this same integer k (without any remainder):

$k = \frac{N}{4008}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 4008 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 4008 less than 100000):

1 × 4008 = 4008
2 × 4008 = 8016
3 × 4008 = 12024
...
23 × 4008 = 92184
24 × 4008 = 96192