What are the numbers divisible by 4012?

4012, 8024, 12036, 16048, 20060, 24072, 28084, 32096, 36108, 40120, 44132, 48144, 52156, 56168, 60180, 64192, 68204, 72216, 76228, 80240, 84252, 88264, 92276, 96288

There is a total of 24 numbers (up to 100000) that are divisible by 4012.
The sum of these numbers is 1203600.
The arithmetic mean of these numbers is 50150.

How to find the numbers divisible by 4012?

Finding all the numbers that can be divided by 4012 is essentially the same as searching for the multiples of 4012: if a number N is a multiple of 4012, then 4012 is a divisor of N.

Indeed, if we assume that N is a multiple of 4012, this means there exists an integer k such that:

$k \times 4012 = N$

Conversely, the result of N divided by 4012 is this same integer k (without any remainder):

$k = \frac{N}{4012}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 4012 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 4012 less than 100000):

1 × 4012 = 4012
2 × 4012 = 8024
3 × 4012 = 12036
...
23 × 4012 = 92276
24 × 4012 = 96288