What are the numbers divisible by 536?

536, 1072, 1608, 2144, 2680, 3216, 3752, 4288, 4824, 5360, 5896, 6432, 6968, 7504, 8040, 8576, 9112, 9648, 10184, 10720, 11256, 11792, 12328, 12864, 13400, 13936, 14472, 15008, 15544, 16080, 16616, 17152, 17688, 18224, 18760, 19296, 19832, 20368, 20904, 21440, 21976, 22512, 23048, 23584, 24120, 24656, 25192, 25728, 26264, 26800, 27336, 27872, 28408, 28944, 29480, 30016, 30552, 31088, 31624, 32160, 32696, 33232, 33768, 34304, 34840, 35376, 35912, 36448, 36984, 37520, 38056, 38592, 39128, 39664, 40200, 40736, 41272, 41808, 42344, 42880, 43416, 43952, 44488, 45024, 45560, 46096, 46632, 47168, 47704, 48240, 48776, 49312, 49848, 50384, 50920, 51456, 51992, 52528, 53064, 53600, 54136, 54672, 55208, 55744, 56280, 56816, 57352, 57888, 58424, 58960, 59496, 60032, 60568, 61104, 61640, 62176, 62712, 63248, 63784, 64320, 64856, 65392, 65928, 66464, 67000, 67536, 68072, 68608, 69144, 69680, 70216, 70752, 71288, 71824, 72360, 72896, 73432, 73968, 74504, 75040, 75576, 76112, 76648, 77184, 77720, 78256, 78792, 79328, 79864, 80400, 80936, 81472, 82008, 82544, 83080, 83616, 84152, 84688, 85224, 85760, 86296, 86832, 87368, 87904, 88440, 88976, 89512, 90048, 90584, 91120, 91656, 92192, 92728, 93264, 93800, 94336, 94872, 95408, 95944, 96480, 97016, 97552, 98088, 98624, 99160, 99696

There is a total of 186 numbers (up to 100000) that are divisible by 536.
The sum of these numbers is 9321576.
The arithmetic mean of these numbers is 50116.

How to find the numbers divisible by 536?

Finding all the numbers that can be divided by 536 is essentially the same as searching for the multiples of 536: if a number N is a multiple of 536, then 536 is a divisor of N.

Indeed, if we assume that N is a multiple of 536, this means there exists an integer k such that:

$k \times 536 = N$

Conversely, the result of N divided by 536 is this same integer k (without any remainder):

$k = \frac{N}{536}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 536 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 536 less than 100000):

1 × 536 = 536
2 × 536 = 1072
3 × 536 = 1608
...
185 × 536 = 99160
186 × 536 = 99696