What are the numbers divisible by 701?

701, 1402, 2103, 2804, 3505, 4206, 4907, 5608, 6309, 7010, 7711, 8412, 9113, 9814, 10515, 11216, 11917, 12618, 13319, 14020, 14721, 15422, 16123, 16824, 17525, 18226, 18927, 19628, 20329, 21030, 21731, 22432, 23133, 23834, 24535, 25236, 25937, 26638, 27339, 28040, 28741, 29442, 30143, 30844, 31545, 32246, 32947, 33648, 34349, 35050, 35751, 36452, 37153, 37854, 38555, 39256, 39957, 40658, 41359, 42060, 42761, 43462, 44163, 44864, 45565, 46266, 46967, 47668, 48369, 49070, 49771, 50472, 51173, 51874, 52575, 53276, 53977, 54678, 55379, 56080, 56781, 57482, 58183, 58884, 59585, 60286, 60987, 61688, 62389, 63090, 63791, 64492, 65193, 65894, 66595, 67296, 67997, 68698, 69399, 70100, 70801, 71502, 72203, 72904, 73605, 74306, 75007, 75708, 76409, 77110, 77811, 78512, 79213, 79914, 80615, 81316, 82017, 82718, 83419, 84120, 84821, 85522, 86223, 86924, 87625, 88326, 89027, 89728, 90429, 91130, 91831, 92532, 93233, 93934, 94635, 95336, 96037, 96738, 97439, 98140, 98841, 99542

There is a total of 142 numbers (up to 100000) that are divisible by 701.
The sum of these numbers is 7117253.
The arithmetic mean of these numbers is 50121.5.

How to find the numbers divisible by 701?

Finding all the numbers that can be divided by 701 is essentially the same as searching for the multiples of 701: if a number N is a multiple of 701, then 701 is a divisor of N.

Indeed, if we assume that N is a multiple of 701, this means there exists an integer k such that:

$k \times 701 = N$

Conversely, the result of N divided by 701 is this same integer k (without any remainder):

$k = \frac{N}{701}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 701 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 701 less than 100000):

1 × 701 = 701
2 × 701 = 1402
3 × 701 = 2103
...
141 × 701 = 98841
142 × 701 = 99542