What are the numbers divisible by 720?

720, 1440, 2160, 2880, 3600, 4320, 5040, 5760, 6480, 7200, 7920, 8640, 9360, 10080, 10800, 11520, 12240, 12960, 13680, 14400, 15120, 15840, 16560, 17280, 18000, 18720, 19440, 20160, 20880, 21600, 22320, 23040, 23760, 24480, 25200, 25920, 26640, 27360, 28080, 28800, 29520, 30240, 30960, 31680, 32400, 33120, 33840, 34560, 35280, 36000, 36720, 37440, 38160, 38880, 39600, 40320, 41040, 41760, 42480, 43200, 43920, 44640, 45360, 46080, 46800, 47520, 48240, 48960, 49680, 50400, 51120, 51840, 52560, 53280, 54000, 54720, 55440, 56160, 56880, 57600, 58320, 59040, 59760, 60480, 61200, 61920, 62640, 63360, 64080, 64800, 65520, 66240, 66960, 67680, 68400, 69120, 69840, 70560, 71280, 72000, 72720, 73440, 74160, 74880, 75600, 76320, 77040, 77760, 78480, 79200, 79920, 80640, 81360, 82080, 82800, 83520, 84240, 84960, 85680, 86400, 87120, 87840, 88560, 89280, 90000, 90720, 91440, 92160, 92880, 93600, 94320, 95040, 95760, 96480, 97200, 97920, 98640, 99360

There is a total of 138 numbers (up to 100000) that are divisible by 720.
The sum of these numbers is 6905520.
The arithmetic mean of these numbers is 50040.

How to find the numbers divisible by 720?

Finding all the numbers that can be divided by 720 is essentially the same as searching for the multiples of 720: if a number N is a multiple of 720, then 720 is a divisor of N.

Indeed, if we assume that N is a multiple of 720, this means there exists an integer k such that:

$k \times 720 = N$

Conversely, the result of N divided by 720 is this same integer k (without any remainder):

$k = \frac{N}{720}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 720 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 720 less than 100000):

1 × 720 = 720
2 × 720 = 1440
3 × 720 = 2160
...
137 × 720 = 98640
138 × 720 = 99360