What are the numbers divisible by 740?

740, 1480, 2220, 2960, 3700, 4440, 5180, 5920, 6660, 7400, 8140, 8880, 9620, 10360, 11100, 11840, 12580, 13320, 14060, 14800, 15540, 16280, 17020, 17760, 18500, 19240, 19980, 20720, 21460, 22200, 22940, 23680, 24420, 25160, 25900, 26640, 27380, 28120, 28860, 29600, 30340, 31080, 31820, 32560, 33300, 34040, 34780, 35520, 36260, 37000, 37740, 38480, 39220, 39960, 40700, 41440, 42180, 42920, 43660, 44400, 45140, 45880, 46620, 47360, 48100, 48840, 49580, 50320, 51060, 51800, 52540, 53280, 54020, 54760, 55500, 56240, 56980, 57720, 58460, 59200, 59940, 60680, 61420, 62160, 62900, 63640, 64380, 65120, 65860, 66600, 67340, 68080, 68820, 69560, 70300, 71040, 71780, 72520, 73260, 74000, 74740, 75480, 76220, 76960, 77700, 78440, 79180, 79920, 80660, 81400, 82140, 82880, 83620, 84360, 85100, 85840, 86580, 87320, 88060, 88800, 89540, 90280, 91020, 91760, 92500, 93240, 93980, 94720, 95460, 96200, 96940, 97680, 98420, 99160, 99900

There is a total of 135 numbers (up to 100000) that are divisible by 740.
The sum of these numbers is 6793200.
The arithmetic mean of these numbers is 50320.

How to find the numbers divisible by 740?

Finding all the numbers that can be divided by 740 is essentially the same as searching for the multiples of 740: if a number N is a multiple of 740, then 740 is a divisor of N.

Indeed, if we assume that N is a multiple of 740, this means there exists an integer k such that:

$k \times 740 = N$

Conversely, the result of N divided by 740 is this same integer k (without any remainder):

$k = \frac{N}{740}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 740 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 740 less than 100000):

1 × 740 = 740
2 × 740 = 1480
3 × 740 = 2220
...
134 × 740 = 99160
135 × 740 = 99900