What are the numbers divisible by 751?

751, 1502, 2253, 3004, 3755, 4506, 5257, 6008, 6759, 7510, 8261, 9012, 9763, 10514, 11265, 12016, 12767, 13518, 14269, 15020, 15771, 16522, 17273, 18024, 18775, 19526, 20277, 21028, 21779, 22530, 23281, 24032, 24783, 25534, 26285, 27036, 27787, 28538, 29289, 30040, 30791, 31542, 32293, 33044, 33795, 34546, 35297, 36048, 36799, 37550, 38301, 39052, 39803, 40554, 41305, 42056, 42807, 43558, 44309, 45060, 45811, 46562, 47313, 48064, 48815, 49566, 50317, 51068, 51819, 52570, 53321, 54072, 54823, 55574, 56325, 57076, 57827, 58578, 59329, 60080, 60831, 61582, 62333, 63084, 63835, 64586, 65337, 66088, 66839, 67590, 68341, 69092, 69843, 70594, 71345, 72096, 72847, 73598, 74349, 75100, 75851, 76602, 77353, 78104, 78855, 79606, 80357, 81108, 81859, 82610, 83361, 84112, 84863, 85614, 86365, 87116, 87867, 88618, 89369, 90120, 90871, 91622, 92373, 93124, 93875, 94626, 95377, 96128, 96879, 97630, 98381, 99132, 99883

There is a total of 133 numbers (up to 100000) that are divisible by 751.
The sum of these numbers is 6692161.
The arithmetic mean of these numbers is 50317.

How to find the numbers divisible by 751?

Finding all the numbers that can be divided by 751 is essentially the same as searching for the multiples of 751: if a number N is a multiple of 751, then 751 is a divisor of N.

Indeed, if we assume that N is a multiple of 751, this means there exists an integer k such that:

$k \times 751 = N$

Conversely, the result of N divided by 751 is this same integer k (without any remainder):

$k = \frac{N}{751}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 751 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 751 less than 100000):

1 × 751 = 751
2 × 751 = 1502
3 × 751 = 2253
...
132 × 751 = 99132
133 × 751 = 99883