What are the numbers divisible by 760?

760, 1520, 2280, 3040, 3800, 4560, 5320, 6080, 6840, 7600, 8360, 9120, 9880, 10640, 11400, 12160, 12920, 13680, 14440, 15200, 15960, 16720, 17480, 18240, 19000, 19760, 20520, 21280, 22040, 22800, 23560, 24320, 25080, 25840, 26600, 27360, 28120, 28880, 29640, 30400, 31160, 31920, 32680, 33440, 34200, 34960, 35720, 36480, 37240, 38000, 38760, 39520, 40280, 41040, 41800, 42560, 43320, 44080, 44840, 45600, 46360, 47120, 47880, 48640, 49400, 50160, 50920, 51680, 52440, 53200, 53960, 54720, 55480, 56240, 57000, 57760, 58520, 59280, 60040, 60800, 61560, 62320, 63080, 63840, 64600, 65360, 66120, 66880, 67640, 68400, 69160, 69920, 70680, 71440, 72200, 72960, 73720, 74480, 75240, 76000, 76760, 77520, 78280, 79040, 79800, 80560, 81320, 82080, 82840, 83600, 84360, 85120, 85880, 86640, 87400, 88160, 88920, 89680, 90440, 91200, 91960, 92720, 93480, 94240, 95000, 95760, 96520, 97280, 98040, 98800, 99560

There is a total of 131 numbers (up to 100000) that are divisible by 760.
The sum of these numbers is 6570960.
The arithmetic mean of these numbers is 50160.

How to find the numbers divisible by 760?

Finding all the numbers that can be divided by 760 is essentially the same as searching for the multiples of 760: if a number N is a multiple of 760, then 760 is a divisor of N.

Indeed, if we assume that N is a multiple of 760, this means there exists an integer k such that:

$k \times 760 = N$

Conversely, the result of N divided by 760 is this same integer k (without any remainder):

$k = \frac{N}{760}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 760 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 760 less than 100000):

1 × 760 = 760
2 × 760 = 1520
3 × 760 = 2280
...
130 × 760 = 98800
131 × 760 = 99560