What are the numbers divisible by 790?

790, 1580, 2370, 3160, 3950, 4740, 5530, 6320, 7110, 7900, 8690, 9480, 10270, 11060, 11850, 12640, 13430, 14220, 15010, 15800, 16590, 17380, 18170, 18960, 19750, 20540, 21330, 22120, 22910, 23700, 24490, 25280, 26070, 26860, 27650, 28440, 29230, 30020, 30810, 31600, 32390, 33180, 33970, 34760, 35550, 36340, 37130, 37920, 38710, 39500, 40290, 41080, 41870, 42660, 43450, 44240, 45030, 45820, 46610, 47400, 48190, 48980, 49770, 50560, 51350, 52140, 52930, 53720, 54510, 55300, 56090, 56880, 57670, 58460, 59250, 60040, 60830, 61620, 62410, 63200, 63990, 64780, 65570, 66360, 67150, 67940, 68730, 69520, 70310, 71100, 71890, 72680, 73470, 74260, 75050, 75840, 76630, 77420, 78210, 79000, 79790, 80580, 81370, 82160, 82950, 83740, 84530, 85320, 86110, 86900, 87690, 88480, 89270, 90060, 90850, 91640, 92430, 93220, 94010, 94800, 95590, 96380, 97170, 97960, 98750, 99540

There is a total of 126 numbers (up to 100000) that are divisible by 790.
The sum of these numbers is 6320790.
The arithmetic mean of these numbers is 50165.

How to find the numbers divisible by 790?

Finding all the numbers that can be divided by 790 is essentially the same as searching for the multiples of 790: if a number N is a multiple of 790, then 790 is a divisor of N.

Indeed, if we assume that N is a multiple of 790, this means there exists an integer k such that:

$k \times 790 = N$

Conversely, the result of N divided by 790 is this same integer k (without any remainder):

$k = \frac{N}{790}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 790 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 790 less than 100000):

1 × 790 = 790
2 × 790 = 1580
3 × 790 = 2370
...
125 × 790 = 98750
126 × 790 = 99540