What are the numbers divisible by 795?

795, 1590, 2385, 3180, 3975, 4770, 5565, 6360, 7155, 7950, 8745, 9540, 10335, 11130, 11925, 12720, 13515, 14310, 15105, 15900, 16695, 17490, 18285, 19080, 19875, 20670, 21465, 22260, 23055, 23850, 24645, 25440, 26235, 27030, 27825, 28620, 29415, 30210, 31005, 31800, 32595, 33390, 34185, 34980, 35775, 36570, 37365, 38160, 38955, 39750, 40545, 41340, 42135, 42930, 43725, 44520, 45315, 46110, 46905, 47700, 48495, 49290, 50085, 50880, 51675, 52470, 53265, 54060, 54855, 55650, 56445, 57240, 58035, 58830, 59625, 60420, 61215, 62010, 62805, 63600, 64395, 65190, 65985, 66780, 67575, 68370, 69165, 69960, 70755, 71550, 72345, 73140, 73935, 74730, 75525, 76320, 77115, 77910, 78705, 79500, 80295, 81090, 81885, 82680, 83475, 84270, 85065, 85860, 86655, 87450, 88245, 89040, 89835, 90630, 91425, 92220, 93015, 93810, 94605, 95400, 96195, 96990, 97785, 98580, 99375

There is a total of 125 numbers (up to 100000) that are divisible by 795.
The sum of these numbers is 6260625.
The arithmetic mean of these numbers is 50085.

How to find the numbers divisible by 795?

Finding all the numbers that can be divided by 795 is essentially the same as searching for the multiples of 795: if a number N is a multiple of 795, then 795 is a divisor of N.

Indeed, if we assume that N is a multiple of 795, this means there exists an integer k such that:

$k \times 795 = N$

Conversely, the result of N divided by 795 is this same integer k (without any remainder):

$k = \frac{N}{795}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 795 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 795 less than 100000):

1 × 795 = 795
2 × 795 = 1590
3 × 795 = 2385
...
124 × 795 = 98580
125 × 795 = 99375