What are the numbers divisible by 802?

802, 1604, 2406, 3208, 4010, 4812, 5614, 6416, 7218, 8020, 8822, 9624, 10426, 11228, 12030, 12832, 13634, 14436, 15238, 16040, 16842, 17644, 18446, 19248, 20050, 20852, 21654, 22456, 23258, 24060, 24862, 25664, 26466, 27268, 28070, 28872, 29674, 30476, 31278, 32080, 32882, 33684, 34486, 35288, 36090, 36892, 37694, 38496, 39298, 40100, 40902, 41704, 42506, 43308, 44110, 44912, 45714, 46516, 47318, 48120, 48922, 49724, 50526, 51328, 52130, 52932, 53734, 54536, 55338, 56140, 56942, 57744, 58546, 59348, 60150, 60952, 61754, 62556, 63358, 64160, 64962, 65764, 66566, 67368, 68170, 68972, 69774, 70576, 71378, 72180, 72982, 73784, 74586, 75388, 76190, 76992, 77794, 78596, 79398, 80200, 81002, 81804, 82606, 83408, 84210, 85012, 85814, 86616, 87418, 88220, 89022, 89824, 90626, 91428, 92230, 93032, 93834, 94636, 95438, 96240, 97042, 97844, 98646, 99448

There is a total of 124 numbers (up to 100000) that are divisible by 802.
The sum of these numbers is 6215500.
The arithmetic mean of these numbers is 50125.

How to find the numbers divisible by 802?

Finding all the numbers that can be divided by 802 is essentially the same as searching for the multiples of 802: if a number N is a multiple of 802, then 802 is a divisor of N.

Indeed, if we assume that N is a multiple of 802, this means there exists an integer k such that:

$k \times 802 = N$

Conversely, the result of N divided by 802 is this same integer k (without any remainder):

$k = \frac{N}{802}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 802 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 802 less than 100000):

1 × 802 = 802
2 × 802 = 1604
3 × 802 = 2406
...
123 × 802 = 98646
124 × 802 = 99448