What are the numbers divisible by 804?

804, 1608, 2412, 3216, 4020, 4824, 5628, 6432, 7236, 8040, 8844, 9648, 10452, 11256, 12060, 12864, 13668, 14472, 15276, 16080, 16884, 17688, 18492, 19296, 20100, 20904, 21708, 22512, 23316, 24120, 24924, 25728, 26532, 27336, 28140, 28944, 29748, 30552, 31356, 32160, 32964, 33768, 34572, 35376, 36180, 36984, 37788, 38592, 39396, 40200, 41004, 41808, 42612, 43416, 44220, 45024, 45828, 46632, 47436, 48240, 49044, 49848, 50652, 51456, 52260, 53064, 53868, 54672, 55476, 56280, 57084, 57888, 58692, 59496, 60300, 61104, 61908, 62712, 63516, 64320, 65124, 65928, 66732, 67536, 68340, 69144, 69948, 70752, 71556, 72360, 73164, 73968, 74772, 75576, 76380, 77184, 77988, 78792, 79596, 80400, 81204, 82008, 82812, 83616, 84420, 85224, 86028, 86832, 87636, 88440, 89244, 90048, 90852, 91656, 92460, 93264, 94068, 94872, 95676, 96480, 97284, 98088, 98892, 99696

There is a total of 124 numbers (up to 100000) that are divisible by 804.
The sum of these numbers is 6231000.
The arithmetic mean of these numbers is 50250.

How to find the numbers divisible by 804?

Finding all the numbers that can be divided by 804 is essentially the same as searching for the multiples of 804: if a number N is a multiple of 804, then 804 is a divisor of N.

Indeed, if we assume that N is a multiple of 804, this means there exists an integer k such that:

$k \times 804 = N$

Conversely, the result of N divided by 804 is this same integer k (without any remainder):

$k = \frac{N}{804}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 804 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 804 less than 100000):

1 × 804 = 804
2 × 804 = 1608
3 × 804 = 2412
...
123 × 804 = 98892
124 × 804 = 99696