What are the numbers divisible by 809?

809, 1618, 2427, 3236, 4045, 4854, 5663, 6472, 7281, 8090, 8899, 9708, 10517, 11326, 12135, 12944, 13753, 14562, 15371, 16180, 16989, 17798, 18607, 19416, 20225, 21034, 21843, 22652, 23461, 24270, 25079, 25888, 26697, 27506, 28315, 29124, 29933, 30742, 31551, 32360, 33169, 33978, 34787, 35596, 36405, 37214, 38023, 38832, 39641, 40450, 41259, 42068, 42877, 43686, 44495, 45304, 46113, 46922, 47731, 48540, 49349, 50158, 50967, 51776, 52585, 53394, 54203, 55012, 55821, 56630, 57439, 58248, 59057, 59866, 60675, 61484, 62293, 63102, 63911, 64720, 65529, 66338, 67147, 67956, 68765, 69574, 70383, 71192, 72001, 72810, 73619, 74428, 75237, 76046, 76855, 77664, 78473, 79282, 80091, 80900, 81709, 82518, 83327, 84136, 84945, 85754, 86563, 87372, 88181, 88990, 89799, 90608, 91417, 92226, 93035, 93844, 94653, 95462, 96271, 97080, 97889, 98698, 99507

There is a total of 123 numbers (up to 100000) that are divisible by 809.
The sum of these numbers is 6169434.
The arithmetic mean of these numbers is 50158.

How to find the numbers divisible by 809?

Finding all the numbers that can be divided by 809 is essentially the same as searching for the multiples of 809: if a number N is a multiple of 809, then 809 is a divisor of N.

Indeed, if we assume that N is a multiple of 809, this means there exists an integer k such that:

$k \times 809 = N$

Conversely, the result of N divided by 809 is this same integer k (without any remainder):

$k = \frac{N}{809}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 809 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 809 less than 100000):

1 × 809 = 809
2 × 809 = 1618
3 × 809 = 2427
...
122 × 809 = 98698
123 × 809 = 99507