What are the numbers divisible by 830?

830, 1660, 2490, 3320, 4150, 4980, 5810, 6640, 7470, 8300, 9130, 9960, 10790, 11620, 12450, 13280, 14110, 14940, 15770, 16600, 17430, 18260, 19090, 19920, 20750, 21580, 22410, 23240, 24070, 24900, 25730, 26560, 27390, 28220, 29050, 29880, 30710, 31540, 32370, 33200, 34030, 34860, 35690, 36520, 37350, 38180, 39010, 39840, 40670, 41500, 42330, 43160, 43990, 44820, 45650, 46480, 47310, 48140, 48970, 49800, 50630, 51460, 52290, 53120, 53950, 54780, 55610, 56440, 57270, 58100, 58930, 59760, 60590, 61420, 62250, 63080, 63910, 64740, 65570, 66400, 67230, 68060, 68890, 69720, 70550, 71380, 72210, 73040, 73870, 74700, 75530, 76360, 77190, 78020, 78850, 79680, 80510, 81340, 82170, 83000, 83830, 84660, 85490, 86320, 87150, 87980, 88810, 89640, 90470, 91300, 92130, 92960, 93790, 94620, 95450, 96280, 97110, 97940, 98770, 99600

There is a total of 120 numbers (up to 100000) that are divisible by 830.
The sum of these numbers is 6025800.
The arithmetic mean of these numbers is 50215.

How to find the numbers divisible by 830?

Finding all the numbers that can be divided by 830 is essentially the same as searching for the multiples of 830: if a number N is a multiple of 830, then 830 is a divisor of N.

Indeed, if we assume that N is a multiple of 830, this means there exists an integer k such that:

$k \times 830 = N$

Conversely, the result of N divided by 830 is this same integer k (without any remainder):

$k = \frac{N}{830}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 830 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 830 less than 100000):

1 × 830 = 830
2 × 830 = 1660
3 × 830 = 2490
...
119 × 830 = 98770
120 × 830 = 99600