What are the numbers divisible by 838?

838, 1676, 2514, 3352, 4190, 5028, 5866, 6704, 7542, 8380, 9218, 10056, 10894, 11732, 12570, 13408, 14246, 15084, 15922, 16760, 17598, 18436, 19274, 20112, 20950, 21788, 22626, 23464, 24302, 25140, 25978, 26816, 27654, 28492, 29330, 30168, 31006, 31844, 32682, 33520, 34358, 35196, 36034, 36872, 37710, 38548, 39386, 40224, 41062, 41900, 42738, 43576, 44414, 45252, 46090, 46928, 47766, 48604, 49442, 50280, 51118, 51956, 52794, 53632, 54470, 55308, 56146, 56984, 57822, 58660, 59498, 60336, 61174, 62012, 62850, 63688, 64526, 65364, 66202, 67040, 67878, 68716, 69554, 70392, 71230, 72068, 72906, 73744, 74582, 75420, 76258, 77096, 77934, 78772, 79610, 80448, 81286, 82124, 82962, 83800, 84638, 85476, 86314, 87152, 87990, 88828, 89666, 90504, 91342, 92180, 93018, 93856, 94694, 95532, 96370, 97208, 98046, 98884, 99722

There is a total of 119 numbers (up to 100000) that are divisible by 838.
The sum of these numbers is 5983320.
The arithmetic mean of these numbers is 50280.

How to find the numbers divisible by 838?

Finding all the numbers that can be divided by 838 is essentially the same as searching for the multiples of 838: if a number N is a multiple of 838, then 838 is a divisor of N.

Indeed, if we assume that N is a multiple of 838, this means there exists an integer k such that:

$k \times 838 = N$

Conversely, the result of N divided by 838 is this same integer k (without any remainder):

$k = \frac{N}{838}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 838 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 838 less than 100000):

1 × 838 = 838
2 × 838 = 1676
3 × 838 = 2514
...
118 × 838 = 98884
119 × 838 = 99722