What are the numbers divisible by 842?

842, 1684, 2526, 3368, 4210, 5052, 5894, 6736, 7578, 8420, 9262, 10104, 10946, 11788, 12630, 13472, 14314, 15156, 15998, 16840, 17682, 18524, 19366, 20208, 21050, 21892, 22734, 23576, 24418, 25260, 26102, 26944, 27786, 28628, 29470, 30312, 31154, 31996, 32838, 33680, 34522, 35364, 36206, 37048, 37890, 38732, 39574, 40416, 41258, 42100, 42942, 43784, 44626, 45468, 46310, 47152, 47994, 48836, 49678, 50520, 51362, 52204, 53046, 53888, 54730, 55572, 56414, 57256, 58098, 58940, 59782, 60624, 61466, 62308, 63150, 63992, 64834, 65676, 66518, 67360, 68202, 69044, 69886, 70728, 71570, 72412, 73254, 74096, 74938, 75780, 76622, 77464, 78306, 79148, 79990, 80832, 81674, 82516, 83358, 84200, 85042, 85884, 86726, 87568, 88410, 89252, 90094, 90936, 91778, 92620, 93462, 94304, 95146, 95988, 96830, 97672, 98514, 99356

There is a total of 118 numbers (up to 100000) that are divisible by 842.
The sum of these numbers is 5911682.
The arithmetic mean of these numbers is 50099.

How to find the numbers divisible by 842?

Finding all the numbers that can be divided by 842 is essentially the same as searching for the multiples of 842: if a number N is a multiple of 842, then 842 is a divisor of N.

Indeed, if we assume that N is a multiple of 842, this means there exists an integer k such that:

$k \times 842 = N$

Conversely, the result of N divided by 842 is this same integer k (without any remainder):

$k = \frac{N}{842}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 842 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 842 less than 100000):

1 × 842 = 842
2 × 842 = 1684
3 × 842 = 2526
...
117 × 842 = 98514
118 × 842 = 99356