What are the numbers divisible by 848?

848, 1696, 2544, 3392, 4240, 5088, 5936, 6784, 7632, 8480, 9328, 10176, 11024, 11872, 12720, 13568, 14416, 15264, 16112, 16960, 17808, 18656, 19504, 20352, 21200, 22048, 22896, 23744, 24592, 25440, 26288, 27136, 27984, 28832, 29680, 30528, 31376, 32224, 33072, 33920, 34768, 35616, 36464, 37312, 38160, 39008, 39856, 40704, 41552, 42400, 43248, 44096, 44944, 45792, 46640, 47488, 48336, 49184, 50032, 50880, 51728, 52576, 53424, 54272, 55120, 55968, 56816, 57664, 58512, 59360, 60208, 61056, 61904, 62752, 63600, 64448, 65296, 66144, 66992, 67840, 68688, 69536, 70384, 71232, 72080, 72928, 73776, 74624, 75472, 76320, 77168, 78016, 78864, 79712, 80560, 81408, 82256, 83104, 83952, 84800, 85648, 86496, 87344, 88192, 89040, 89888, 90736, 91584, 92432, 93280, 94128, 94976, 95824, 96672, 97520, 98368, 99216

There is a total of 117 numbers (up to 100000) that are divisible by 848.
The sum of these numbers is 5853744.
The arithmetic mean of these numbers is 50032.

How to find the numbers divisible by 848?

Finding all the numbers that can be divided by 848 is essentially the same as searching for the multiples of 848: if a number N is a multiple of 848, then 848 is a divisor of N.

Indeed, if we assume that N is a multiple of 848, this means there exists an integer k such that:

$k \times 848 = N$

Conversely, the result of N divided by 848 is this same integer k (without any remainder):

$k = \frac{N}{848}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 848 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 848 less than 100000):

1 × 848 = 848
2 × 848 = 1696
3 × 848 = 2544
...
116 × 848 = 98368
117 × 848 = 99216