What are the numbers divisible by 850?

850, 1700, 2550, 3400, 4250, 5100, 5950, 6800, 7650, 8500, 9350, 10200, 11050, 11900, 12750, 13600, 14450, 15300, 16150, 17000, 17850, 18700, 19550, 20400, 21250, 22100, 22950, 23800, 24650, 25500, 26350, 27200, 28050, 28900, 29750, 30600, 31450, 32300, 33150, 34000, 34850, 35700, 36550, 37400, 38250, 39100, 39950, 40800, 41650, 42500, 43350, 44200, 45050, 45900, 46750, 47600, 48450, 49300, 50150, 51000, 51850, 52700, 53550, 54400, 55250, 56100, 56950, 57800, 58650, 59500, 60350, 61200, 62050, 62900, 63750, 64600, 65450, 66300, 67150, 68000, 68850, 69700, 70550, 71400, 72250, 73100, 73950, 74800, 75650, 76500, 77350, 78200, 79050, 79900, 80750, 81600, 82450, 83300, 84150, 85000, 85850, 86700, 87550, 88400, 89250, 90100, 90950, 91800, 92650, 93500, 94350, 95200, 96050, 96900, 97750, 98600, 99450

There is a total of 117 numbers (up to 100000) that are divisible by 850.
The sum of these numbers is 5867550.
The arithmetic mean of these numbers is 50150.

How to find the numbers divisible by 850?

Finding all the numbers that can be divided by 850 is essentially the same as searching for the multiples of 850: if a number N is a multiple of 850, then 850 is a divisor of N.

Indeed, if we assume that N is a multiple of 850, this means there exists an integer k such that:

$k \times 850 = N$

Conversely, the result of N divided by 850 is this same integer k (without any remainder):

$k = \frac{N}{850}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 850 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 850 less than 100000):

1 × 850 = 850
2 × 850 = 1700
3 × 850 = 2550
...
116 × 850 = 98600
117 × 850 = 99450