What are the numbers divisible by 852?

852, 1704, 2556, 3408, 4260, 5112, 5964, 6816, 7668, 8520, 9372, 10224, 11076, 11928, 12780, 13632, 14484, 15336, 16188, 17040, 17892, 18744, 19596, 20448, 21300, 22152, 23004, 23856, 24708, 25560, 26412, 27264, 28116, 28968, 29820, 30672, 31524, 32376, 33228, 34080, 34932, 35784, 36636, 37488, 38340, 39192, 40044, 40896, 41748, 42600, 43452, 44304, 45156, 46008, 46860, 47712, 48564, 49416, 50268, 51120, 51972, 52824, 53676, 54528, 55380, 56232, 57084, 57936, 58788, 59640, 60492, 61344, 62196, 63048, 63900, 64752, 65604, 66456, 67308, 68160, 69012, 69864, 70716, 71568, 72420, 73272, 74124, 74976, 75828, 76680, 77532, 78384, 79236, 80088, 80940, 81792, 82644, 83496, 84348, 85200, 86052, 86904, 87756, 88608, 89460, 90312, 91164, 92016, 92868, 93720, 94572, 95424, 96276, 97128, 97980, 98832, 99684

There is a total of 117 numbers (up to 100000) that are divisible by 852.
The sum of these numbers is 5881356.
The arithmetic mean of these numbers is 50268.

How to find the numbers divisible by 852?

Finding all the numbers that can be divided by 852 is essentially the same as searching for the multiples of 852: if a number N is a multiple of 852, then 852 is a divisor of N.

Indeed, if we assume that N is a multiple of 852, this means there exists an integer k such that:

$k \times 852 = N$

Conversely, the result of N divided by 852 is this same integer k (without any remainder):

$k = \frac{N}{852}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 852 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 852 less than 100000):

1 × 852 = 852
2 × 852 = 1704
3 × 852 = 2556
...
116 × 852 = 98832
117 × 852 = 99684