What are the numbers divisible by 868?

868, 1736, 2604, 3472, 4340, 5208, 6076, 6944, 7812, 8680, 9548, 10416, 11284, 12152, 13020, 13888, 14756, 15624, 16492, 17360, 18228, 19096, 19964, 20832, 21700, 22568, 23436, 24304, 25172, 26040, 26908, 27776, 28644, 29512, 30380, 31248, 32116, 32984, 33852, 34720, 35588, 36456, 37324, 38192, 39060, 39928, 40796, 41664, 42532, 43400, 44268, 45136, 46004, 46872, 47740, 48608, 49476, 50344, 51212, 52080, 52948, 53816, 54684, 55552, 56420, 57288, 58156, 59024, 59892, 60760, 61628, 62496, 63364, 64232, 65100, 65968, 66836, 67704, 68572, 69440, 70308, 71176, 72044, 72912, 73780, 74648, 75516, 76384, 77252, 78120, 78988, 79856, 80724, 81592, 82460, 83328, 84196, 85064, 85932, 86800, 87668, 88536, 89404, 90272, 91140, 92008, 92876, 93744, 94612, 95480, 96348, 97216, 98084, 98952, 99820

There is a total of 115 numbers (up to 100000) that are divisible by 868.
The sum of these numbers is 5789560.
The arithmetic mean of these numbers is 50344.

How to find the numbers divisible by 868?

Finding all the numbers that can be divided by 868 is essentially the same as searching for the multiples of 868: if a number N is a multiple of 868, then 868 is a divisor of N.

Indeed, if we assume that N is a multiple of 868, this means there exists an integer k such that:

$k \times 868 = N$

Conversely, the result of N divided by 868 is this same integer k (without any remainder):

$k = \frac{N}{868}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 868 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 868 less than 100000):

1 × 868 = 868
2 × 868 = 1736
3 × 868 = 2604
...
114 × 868 = 98952
115 × 868 = 99820