What are the numbers divisible by 871?

871, 1742, 2613, 3484, 4355, 5226, 6097, 6968, 7839, 8710, 9581, 10452, 11323, 12194, 13065, 13936, 14807, 15678, 16549, 17420, 18291, 19162, 20033, 20904, 21775, 22646, 23517, 24388, 25259, 26130, 27001, 27872, 28743, 29614, 30485, 31356, 32227, 33098, 33969, 34840, 35711, 36582, 37453, 38324, 39195, 40066, 40937, 41808, 42679, 43550, 44421, 45292, 46163, 47034, 47905, 48776, 49647, 50518, 51389, 52260, 53131, 54002, 54873, 55744, 56615, 57486, 58357, 59228, 60099, 60970, 61841, 62712, 63583, 64454, 65325, 66196, 67067, 67938, 68809, 69680, 70551, 71422, 72293, 73164, 74035, 74906, 75777, 76648, 77519, 78390, 79261, 80132, 81003, 81874, 82745, 83616, 84487, 85358, 86229, 87100, 87971, 88842, 89713, 90584, 91455, 92326, 93197, 94068, 94939, 95810, 96681, 97552, 98423, 99294

There is a total of 114 numbers (up to 100000) that are divisible by 871.
The sum of these numbers is 5709405.
The arithmetic mean of these numbers is 50082.5.

How to find the numbers divisible by 871?

Finding all the numbers that can be divided by 871 is essentially the same as searching for the multiples of 871: if a number N is a multiple of 871, then 871 is a divisor of N.

Indeed, if we assume that N is a multiple of 871, this means there exists an integer k such that:

$k \times 871 = N$

Conversely, the result of N divided by 871 is this same integer k (without any remainder):

$k = \frac{N}{871}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 871 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 871 less than 100000):

1 × 871 = 871
2 × 871 = 1742
3 × 871 = 2613
...
113 × 871 = 98423
114 × 871 = 99294