What are the numbers divisible by 879?

879, 1758, 2637, 3516, 4395, 5274, 6153, 7032, 7911, 8790, 9669, 10548, 11427, 12306, 13185, 14064, 14943, 15822, 16701, 17580, 18459, 19338, 20217, 21096, 21975, 22854, 23733, 24612, 25491, 26370, 27249, 28128, 29007, 29886, 30765, 31644, 32523, 33402, 34281, 35160, 36039, 36918, 37797, 38676, 39555, 40434, 41313, 42192, 43071, 43950, 44829, 45708, 46587, 47466, 48345, 49224, 50103, 50982, 51861, 52740, 53619, 54498, 55377, 56256, 57135, 58014, 58893, 59772, 60651, 61530, 62409, 63288, 64167, 65046, 65925, 66804, 67683, 68562, 69441, 70320, 71199, 72078, 72957, 73836, 74715, 75594, 76473, 77352, 78231, 79110, 79989, 80868, 81747, 82626, 83505, 84384, 85263, 86142, 87021, 87900, 88779, 89658, 90537, 91416, 92295, 93174, 94053, 94932, 95811, 96690, 97569, 98448, 99327

There is a total of 113 numbers (up to 100000) that are divisible by 879.
The sum of these numbers is 5661639.
The arithmetic mean of these numbers is 50103.

How to find the numbers divisible by 879?

Finding all the numbers that can be divided by 879 is essentially the same as searching for the multiples of 879: if a number N is a multiple of 879, then 879 is a divisor of N.

Indeed, if we assume that N is a multiple of 879, this means there exists an integer k such that:

$k \times 879 = N$

Conversely, the result of N divided by 879 is this same integer k (without any remainder):

$k = \frac{N}{879}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 879 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 879 less than 100000):

1 × 879 = 879
2 × 879 = 1758
3 × 879 = 2637
...
112 × 879 = 98448
113 × 879 = 99327