What are the numbers divisible by 9121?

9121, 18242, 27363, 36484, 45605, 54726, 63847, 72968, 82089, 91210

There is a total of 10 numbers (up to 100000) that are divisible by 9121.
The sum of these numbers is 501655.
The arithmetic mean of these numbers is 50165.5.

How to find the numbers divisible by 9121?

Finding all the numbers that can be divided by 9121 is essentially the same as searching for the multiples of 9121: if a number N is a multiple of 9121, then 9121 is a divisor of N.

Indeed, if we assume that N is a multiple of 9121, this means there exists an integer k such that:

$k \times 9121 = N$

Conversely, the result of N divided by 9121 is this same integer k (without any remainder):

$k = \frac{N}{9121}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 9121 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 9121 less than 100000):

1 × 9121 = 9121
2 × 9121 = 18242
3 × 9121 = 27363
...
9 × 9121 = 82089
10 × 9121 = 91210