What are the numbers divisible by 920?

920, 1840, 2760, 3680, 4600, 5520, 6440, 7360, 8280, 9200, 10120, 11040, 11960, 12880, 13800, 14720, 15640, 16560, 17480, 18400, 19320, 20240, 21160, 22080, 23000, 23920, 24840, 25760, 26680, 27600, 28520, 29440, 30360, 31280, 32200, 33120, 34040, 34960, 35880, 36800, 37720, 38640, 39560, 40480, 41400, 42320, 43240, 44160, 45080, 46000, 46920, 47840, 48760, 49680, 50600, 51520, 52440, 53360, 54280, 55200, 56120, 57040, 57960, 58880, 59800, 60720, 61640, 62560, 63480, 64400, 65320, 66240, 67160, 68080, 69000, 69920, 70840, 71760, 72680, 73600, 74520, 75440, 76360, 77280, 78200, 79120, 80040, 80960, 81880, 82800, 83720, 84640, 85560, 86480, 87400, 88320, 89240, 90160, 91080, 92000, 92920, 93840, 94760, 95680, 96600, 97520, 98440, 99360

There is a total of 108 numbers (up to 100000) that are divisible by 920.
The sum of these numbers is 5415120.
The arithmetic mean of these numbers is 50140.

How to find the numbers divisible by 920?

Finding all the numbers that can be divided by 920 is essentially the same as searching for the multiples of 920: if a number N is a multiple of 920, then 920 is a divisor of N.

Indeed, if we assume that N is a multiple of 920, this means there exists an integer k such that:

$k \times 920 = N$

Conversely, the result of N divided by 920 is this same integer k (without any remainder):

$k = \frac{N}{920}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 920 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 920 less than 100000):

1 × 920 = 920
2 × 920 = 1840
3 × 920 = 2760
...
107 × 920 = 98440
108 × 920 = 99360