What are the numbers divisible by 925?

925, 1850, 2775, 3700, 4625, 5550, 6475, 7400, 8325, 9250, 10175, 11100, 12025, 12950, 13875, 14800, 15725, 16650, 17575, 18500, 19425, 20350, 21275, 22200, 23125, 24050, 24975, 25900, 26825, 27750, 28675, 29600, 30525, 31450, 32375, 33300, 34225, 35150, 36075, 37000, 37925, 38850, 39775, 40700, 41625, 42550, 43475, 44400, 45325, 46250, 47175, 48100, 49025, 49950, 50875, 51800, 52725, 53650, 54575, 55500, 56425, 57350, 58275, 59200, 60125, 61050, 61975, 62900, 63825, 64750, 65675, 66600, 67525, 68450, 69375, 70300, 71225, 72150, 73075, 74000, 74925, 75850, 76775, 77700, 78625, 79550, 80475, 81400, 82325, 83250, 84175, 85100, 86025, 86950, 87875, 88800, 89725, 90650, 91575, 92500, 93425, 94350, 95275, 96200, 97125, 98050, 98975, 99900

There is a total of 108 numbers (up to 100000) that are divisible by 925.
The sum of these numbers is 5444550.
The arithmetic mean of these numbers is 50412.5.

How to find the numbers divisible by 925?

Finding all the numbers that can be divided by 925 is essentially the same as searching for the multiples of 925: if a number N is a multiple of 925, then 925 is a divisor of N.

Indeed, if we assume that N is a multiple of 925, this means there exists an integer k such that:

$k \times 925 = N$

Conversely, the result of N divided by 925 is this same integer k (without any remainder):

$k = \frac{N}{925}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 925 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 925 less than 100000):

1 × 925 = 925
2 × 925 = 1850
3 × 925 = 2775
...
107 × 925 = 98975
108 × 925 = 99900