What are the numbers divisible by 928?

928, 1856, 2784, 3712, 4640, 5568, 6496, 7424, 8352, 9280, 10208, 11136, 12064, 12992, 13920, 14848, 15776, 16704, 17632, 18560, 19488, 20416, 21344, 22272, 23200, 24128, 25056, 25984, 26912, 27840, 28768, 29696, 30624, 31552, 32480, 33408, 34336, 35264, 36192, 37120, 38048, 38976, 39904, 40832, 41760, 42688, 43616, 44544, 45472, 46400, 47328, 48256, 49184, 50112, 51040, 51968, 52896, 53824, 54752, 55680, 56608, 57536, 58464, 59392, 60320, 61248, 62176, 63104, 64032, 64960, 65888, 66816, 67744, 68672, 69600, 70528, 71456, 72384, 73312, 74240, 75168, 76096, 77024, 77952, 78880, 79808, 80736, 81664, 82592, 83520, 84448, 85376, 86304, 87232, 88160, 89088, 90016, 90944, 91872, 92800, 93728, 94656, 95584, 96512, 97440, 98368, 99296

There is a total of 107 numbers (up to 100000) that are divisible by 928.
The sum of these numbers is 5361984.
The arithmetic mean of these numbers is 50112.

How to find the numbers divisible by 928?

Finding all the numbers that can be divided by 928 is essentially the same as searching for the multiples of 928: if a number N is a multiple of 928, then 928 is a divisor of N.

Indeed, if we assume that N is a multiple of 928, this means there exists an integer k such that:

$k \times 928 = N$

Conversely, the result of N divided by 928 is this same integer k (without any remainder):

$k = \frac{N}{928}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 928 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 928 less than 100000):

1 × 928 = 928
2 × 928 = 1856
3 × 928 = 2784
...
106 × 928 = 98368
107 × 928 = 99296