What are the numbers divisible by 930?

930, 1860, 2790, 3720, 4650, 5580, 6510, 7440, 8370, 9300, 10230, 11160, 12090, 13020, 13950, 14880, 15810, 16740, 17670, 18600, 19530, 20460, 21390, 22320, 23250, 24180, 25110, 26040, 26970, 27900, 28830, 29760, 30690, 31620, 32550, 33480, 34410, 35340, 36270, 37200, 38130, 39060, 39990, 40920, 41850, 42780, 43710, 44640, 45570, 46500, 47430, 48360, 49290, 50220, 51150, 52080, 53010, 53940, 54870, 55800, 56730, 57660, 58590, 59520, 60450, 61380, 62310, 63240, 64170, 65100, 66030, 66960, 67890, 68820, 69750, 70680, 71610, 72540, 73470, 74400, 75330, 76260, 77190, 78120, 79050, 79980, 80910, 81840, 82770, 83700, 84630, 85560, 86490, 87420, 88350, 89280, 90210, 91140, 92070, 93000, 93930, 94860, 95790, 96720, 97650, 98580, 99510

There is a total of 107 numbers (up to 100000) that are divisible by 930.
The sum of these numbers is 5373540.
The arithmetic mean of these numbers is 50220.

How to find the numbers divisible by 930?

Finding all the numbers that can be divided by 930 is essentially the same as searching for the multiples of 930: if a number N is a multiple of 930, then 930 is a divisor of N.

Indeed, if we assume that N is a multiple of 930, this means there exists an integer k such that:

$k \times 930 = N$

Conversely, the result of N divided by 930 is this same integer k (without any remainder):

$k = \frac{N}{930}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 930 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 930 less than 100000):

1 × 930 = 930
2 × 930 = 1860
3 × 930 = 2790
...
106 × 930 = 98580
107 × 930 = 99510