What are the numbers divisible by 940?

940, 1880, 2820, 3760, 4700, 5640, 6580, 7520, 8460, 9400, 10340, 11280, 12220, 13160, 14100, 15040, 15980, 16920, 17860, 18800, 19740, 20680, 21620, 22560, 23500, 24440, 25380, 26320, 27260, 28200, 29140, 30080, 31020, 31960, 32900, 33840, 34780, 35720, 36660, 37600, 38540, 39480, 40420, 41360, 42300, 43240, 44180, 45120, 46060, 47000, 47940, 48880, 49820, 50760, 51700, 52640, 53580, 54520, 55460, 56400, 57340, 58280, 59220, 60160, 61100, 62040, 62980, 63920, 64860, 65800, 66740, 67680, 68620, 69560, 70500, 71440, 72380, 73320, 74260, 75200, 76140, 77080, 78020, 78960, 79900, 80840, 81780, 82720, 83660, 84600, 85540, 86480, 87420, 88360, 89300, 90240, 91180, 92120, 93060, 94000, 94940, 95880, 96820, 97760, 98700, 99640

There is a total of 106 numbers (up to 100000) that are divisible by 940.
The sum of these numbers is 5330740.
The arithmetic mean of these numbers is 50290.

How to find the numbers divisible by 940?

Finding all the numbers that can be divided by 940 is essentially the same as searching for the multiples of 940: if a number N is a multiple of 940, then 940 is a divisor of N.

Indeed, if we assume that N is a multiple of 940, this means there exists an integer k such that:

$k \times 940 = N$

Conversely, the result of N divided by 940 is this same integer k (without any remainder):

$k = \frac{N}{940}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 940 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 940 less than 100000):

1 × 940 = 940
2 × 940 = 1880
3 × 940 = 2820
...
105 × 940 = 98700
106 × 940 = 99640