What are the numbers divisible by 942?

942, 1884, 2826, 3768, 4710, 5652, 6594, 7536, 8478, 9420, 10362, 11304, 12246, 13188, 14130, 15072, 16014, 16956, 17898, 18840, 19782, 20724, 21666, 22608, 23550, 24492, 25434, 26376, 27318, 28260, 29202, 30144, 31086, 32028, 32970, 33912, 34854, 35796, 36738, 37680, 38622, 39564, 40506, 41448, 42390, 43332, 44274, 45216, 46158, 47100, 48042, 48984, 49926, 50868, 51810, 52752, 53694, 54636, 55578, 56520, 57462, 58404, 59346, 60288, 61230, 62172, 63114, 64056, 64998, 65940, 66882, 67824, 68766, 69708, 70650, 71592, 72534, 73476, 74418, 75360, 76302, 77244, 78186, 79128, 80070, 81012, 81954, 82896, 83838, 84780, 85722, 86664, 87606, 88548, 89490, 90432, 91374, 92316, 93258, 94200, 95142, 96084, 97026, 97968, 98910, 99852

There is a total of 106 numbers (up to 100000) that are divisible by 942.
The sum of these numbers is 5342082.
The arithmetic mean of these numbers is 50397.

How to find the numbers divisible by 942?

Finding all the numbers that can be divided by 942 is essentially the same as searching for the multiples of 942: if a number N is a multiple of 942, then 942 is a divisor of N.

Indeed, if we assume that N is a multiple of 942, this means there exists an integer k such that:

$k \times 942 = N$

Conversely, the result of N divided by 942 is this same integer k (without any remainder):

$k = \frac{N}{942}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 942 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 942 less than 100000):

1 × 942 = 942
2 × 942 = 1884
3 × 942 = 2826
...
105 × 942 = 98910
106 × 942 = 99852